Mathématiques

Question

on considère l'expression E= (x-3)²+(x-3)(x+3)
1. Développer et réduire E.
2.Factoriser E.
3.Calculer E pour x=5.

2 Réponse

  • 1/E=x^2-6x+9+x^2-9 
    E= 2x^2-6x
    2/ E= 2x(x-3) 
    3/ E= 25-30+9+25-9 
    E= 20
  • 1) E = (x-3)(x-3) + (x-3)(x+3)
    E = x*x-x*3-3*x+3*3+x*x+x*3-3*x-3*3
    E = 2x-3x-3x+9+2x+3x-3x-9
    E = 2x+2x+3x-3x-3x-3x+9-9
    E = 4x-3x-3x
    E = x-3x
    E = -2x

    2) E = (x-3)(x-3) + (x-3)(x+3)
    E = (x-3)[(x-3) + (x+3)]
    E = (x-3)(x-3+x+3)
    E = (x-3)(x+x-3+3)
    E = (x-3)2x
    E = x*2x-3*2x
    E = 2x²-6x

    3) E = 2x²-6x
    E = 2(5*5)-6*5
    E = 2*25-30
    E = 50-30
    E = 20

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