Bonjours, je dois factoriser : C = (4a-21)(9a-7)+(9a-7)(-6a-9) et D= (-7a+1)(a+2)-(-9-5a)(-7a+1)
Mathématiques
lisa95420
Question
Bonjours, je dois factoriser : C = (4a-21)(9a-7)+(9a-7)(-6a-9) et D= (-7a+1)(a+2)-(-9-5a)(-7a+1)
1 Réponse
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1. Réponse Anonyme
Bonjour Lisa95420
[tex]C = (4a-21)(9a-7)+(9a-7)(-6a-9)\\C = (9a-7)[(4a-21)+(-6a-9)]\\C = (9a-7)(4a-21-6a-9)\\\boxed{C = (9a-7)(-2a-30)}[/tex]
[tex]D= (-7a+1)(a+2)-(-9-5a)(-7a+1)\\D= (-7a+1)[(a+2)-(-9-5a)]\\D= (-7a+1)(a+2+9+5a)\\\boxed{D= (-7a+1)(6a+11)}[/tex]