Bonjour, pouvez-vous vérifiez mes résultats SVP ? Merci d'avance ! Factorisez les expressions suivantes : A= (2t+1)²-(t+1)² = [(2t+1)(t+1)] [(2t+1)(t-1)] = (3t
Mathématiques
Salut437
Question
Bonjour, pouvez-vous vérifiez mes résultats SVP ? Merci d'avance !
Factorisez les expressions suivantes :
A= (2t+1)²-(t+1)²
= [(2t+1)(t+1)] [(2t+1)(t-1)]
= (3t+2) 3t
B= (3t-7)²-25
= [(3t-7)+25] [(3t-7)-25]
= (3t-7+25) (3t-7-25)
= (3t+18) (3t-32)
C= (3t+4)²-(2t+3)²
=[(3t+4)(2t+3] [(3t+4)(2t-3)]
= (5t+7) (5t+1)
Factorisez les expressions suivantes :
A= (2t+1)²-(t+1)²
= [(2t+1)(t+1)] [(2t+1)(t-1)]
= (3t+2) 3t
B= (3t-7)²-25
= [(3t-7)+25] [(3t-7)-25]
= (3t-7+25) (3t-7-25)
= (3t+18) (3t-32)
C= (3t+4)²-(2t+3)²
=[(3t+4)(2t+3] [(3t+4)(2t-3)]
= (5t+7) (5t+1)
1 Réponse
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1. Réponse manamanou123
a=(2t+1)²-(t+1)²
=(2t-1-t-1)(2t+1+t+1)
=(t-2)(3t+2)
B= (3t-7)²-25
=(3t-7)²-5²
=(3t-7-5)(3t-7+5)
=(3t-12)(3t-2)
C= (3t+4)²-(2t+3)²
=(3t+4-2t-3)(3t+4+2t+3)
=(t+1)(5t+7)