Mathématiques

Question

Je n'arrive pas à développer ses expressions :
A(x) = (x-4)²
B(x) = 4(x-1)²
C(x) = 2(x+7/2)²
D(x) = 2(x+3)(x-6)

Et à factoriser celle-ci :
E(x) = x²+3x
F(x) = x²+4x+4
G(x) = 9x²-24x+16
H(x) = (x-4)²+(x-4)(x-5)

Merci d'avance

1 Réponse

  • Bonjour,

    A(x) = (x-4)²
    A (x) = x² - 8x + 16

    B(x) = 4(x-1)²
    B (x) = 4 (x² - 2x + 1)
    B (x) = 4x² - 8x + 4

    C(x) = 2(x+7/2)²
    C (x) = 2 (x² + 14/2x + 49/4)
    C (x) = 2x² + 28/2x + 98/4
    C (x) = 2x² + 14x + 24,5

    D(x) = 2(x+3)(x-6)
    D (x) = 2 (x² - 6x + 3x - 18)
    D (x) = 2x² - 12x + 6x - 36
    D (x) = 2x² - 6x - 36

    Factoriser :

    E(x) = x²+3x
    E (x) = x (x + 3)

    F(x) = x²+4x+4
    F (x) = (2 + x)²

    G(x) = 9x²-24x+16
    G (x) = (3x - 4)²

    H(x) = (x-4)²+(x-4)(x-5)
    H (x) = (x - 4) [(x - 4) + (x - 5))
    H (x) = (x - 4) (x - 4 + x - 5)
    H (x) = (x - 4) (2x - 9)

Autres questions