aide moi svp A=(3x+1)(2x-3)-(5x-3) (1-x) calculer pour x=0 svpv

Pour x=0 :

A= (3x+1)(2x-3)-(5x-3)(1-x)
  = [3.(0)+1] [2.(0)-3] - [5.(0)-3] [1-0]
  = 1 . (-3) - [ (-3) . 1 ]
  = -3 - (-3)
  = -3 + 3
  = 0

B= -(12-4x)(2x+3)+3x (x-1)+36
= - [12 -4(0)] [2(0)+3] + 3(0) (0-1) + 36
= - (12-0) (0+3) + 36
= -12.(3) + 36
= - 36 + 36
= 0